删除满足条件的列表中的列表

Question

I'm trying to make a quick OCR for specific use, I know should've just write a preprocessor for normal OCR and that would been faster but this idea came up to me first and I figure I should just try it anyway haha. This program would take a picture on a region of screen and identify the number within it, as of right now, it's only 0 and 1 but I've been working on it and stuck with some problems. Here is my code

while True:
    if keyboard.is_pressed('`'):
        Firstlist =  list(pyautogui.locateAllOnScreen(image[0], confidence = 0.95,region=( 1570 , 990 , 230 , 70 )))
        print(len(Firstlist))
        Firstlist1 = list(pyautogui.locateAllOnScreen(image1, confidence = 0.95,region=( 1570 , 990 , 230 , 70 ))) + Firstlist
        print(len(Firstlist1))
        print(Firstlist) 
        if len(Firstlist) > 0:
            print(Firstlist[0][0])
            #compare all first instance of that number and eliminate all duplicated with in a different of 5 x pixel
        break

Which would identify some predetermined set of number like this on screen and right now, it would give me a set of coordinate for number zero on screen, here is the result , please ignore other parts, it's just me playing around. Problem with this is pyautogui.locateAllOnScreen would sometimes generate duplicate value of the same picture within the coordinate ranging from approx 0-5 pixels if not set the confidence level right.

Example:

Value supposed to be [ (1655,1024,20,26),(1675,1024,20,26) ] but will yield a third value like [ (1655,1024,20,26), (1658,1024,20,26), (1675,1024,20,26) ] .

And that's why I'm trying to make a correction for this. Is there anyway to identified if that x value of second duplicate coordinate is within a range of 0-5 pixels to the first coordinate and just delete it, moving the rest up the ladder so that the number would come up right and in order? Thank you!

Note: I'm still working on learning the list removal process by myself, and read the removing list with lambda to me is like gibberish. Please forgive me if something is wrong. Have a good day y'all!

Answer 1

You can try this.

if len(Firstlist) > 2:
    elems = [f[0] for f in Firstlist]  # create a list of just first index
    i = 0
    while i < len(elems) - 1:  # iterate through the list with i
        j = i + 1
        while j < len(elems):  # iterate through the rest of the list with j
            if abs(elems[i] - elems[j]) <= 5:  # if item at index i is within 5 pixels of item at index j
                del elems[j]   # delete item j and continue
            else:
                j += 1    # otherwise move to next item
        i += 1  #  Move to next i item

Answer 2

list1 = [ (1655,1024,20,26), (1658,1024,20,26), (1675,1024,20,26) ]
x = [list1[0]] + [x for x in list1 if abs(list1[0][0] - x[0]) > 5]
print(x)

Output:

[(1655, 1024, 20, 26), (1675, 1024, 20, 26)]