当我在while循环中的else语句之后使用增量运算符时，它破坏了整个程序并且它不起作用

Question

when i run this code in the terminal i get a blank line that just wait for nothing when i move the "i++;" under the "while(str[i]!='\0')" it works but thats not what i wanted , any help?

int main(){
    printf("hello kiddo");
    char str[20]="hel a awdaw dwa";
    int i=0;
    char *cleanstring;

    while(str[i]!='\0'){
        if(str[i]==' '){
            continue;   
        }
        else{
            printf("%c",str[i]);    
        }
        i++;
    }

    return 0;
}

i dont know what wrong with this code

Answer 1

In addition to Johnny Mopp's comment, notice the difference when adding the \n to your printf your program needs to flush the character and will not until the end of line, which as he says never happens since the loop gets stuck.

int main() {
  printf("hello kiddo");
  char str[20] = "hel a awdaw dwa";
  int i = 0;
  char * cleanstring;

  while (str[i] != '\0') {
    if (str[i] != ' ') {
      printf("%c\n", str[i]);
    }
    i++;
  }

  return 0;
}

Answer 2

i solved this problem editing the "if condition" like that

while(str[i]!='\0'){
        //if(str[i]==' '){
        //    continue;   
        //}
        //else{
        //   printf("%c",str[i]);    
        //}
        //i++;

        if(str[i]!=' '){
            strncat(cleanstring,&str[i],1);
        }           
        i++;

    }

the code was long for no reason and its better right now but , still wanna know why it didn't work in the first time.