[英]Mongoose find, then populate, then rename subdocument
How do I populate an index inside of a list and afterwards rename one of the indexes?如何在列表中填充索引,然后重命名其中一个索引? Say I have the following schema's
假设我有以下架构
const supplierSchema = new mongoose.Schema({
name: String,
address: String,
... (19 other fields)
supplier_id: mongoose.Schema.Types.ObjectId,
});
const itemsSchema = new mongoose.Schema({
name: String,
supplier_id: mongoose.Schema.Types.ObjectId,
item_id: mongoose.Schema.Types.ObjectId,
});
const receiptSchema = new mongoose.Schema({
items: [itemSchema]
receipt_id: mongoose.Schema.Types.ObjectId,
});
const Receipt = mongoose.model('Photo', photoSchema);
My Receipt is populated such that我的收据是这样填充的
Receipt.findById(<insertID>) currently gives:
{
receipt_id: ObjectId("..."),
items: [
{
name: "...",
supplier_id: ObjectId("..."),
item_id: ObjectId("...")
},
{
name: "...",
supplier_id: ObjectId("..."),
item_id: ObjectId("...")
}
],
receipt_id: ObjectId("..."),
}
I would like for it to populate the supplier_id
with name
and address
.我希望它用
name
和address
填充supplier_id
ID。 And then rename the supplier_id
to supplier
.然后将供应商 ID 重命名为
supplier_id
supplier
。
use aggregate with $lookup将聚合与 $lookup 一起使用
Receipt.aggregate([
{$match : {_id : <insertID>} },
{
$lookup : {
from: 'supplier',
localField: 'items.supplier_id',
foreignField: '_id',
as: 'supplier'
}
},
{
$unwind : {
path : "supplier"
}
}
])
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