如何过滤数组object中的数组？

Question

How do i filter roles in this array to return true when "Admin" is found?

const array = [{
    "country": "all",
    "roles": [
        "Normal",
        "Admin",
    ]
}]

Answer 1

Use .filter() and .includes() :

const admins = array.filter((u) => u.roles.includes("Admin"))

Answer 2

1.Did u mean to return a boolean overall?

In Js es6 , you could use .some() MDN web docs

it's nice and simple:)

 const array = [{ "country": "all", "roles": [ "Normal", "Admin", ] }, { "country": "test", "roles": [ "Normal" ] }] const result = array.some(o => Boolean(o.roles.some(role => role === 'Admin'))) console.log(result) // return true

2.Or, did u mean that it returns a new array in which each roles become a boolean depending on having 'Admin' or not?

If it is, .some() works as well:)

Try below:

 const array = [{ "country": "all", "roles": [ "Normal", "Admin", ] }, { "country": "test", "roles": [ "Normal" ] }] const result = array.reduce((acc, curr, index) => { const item = Object.assign({}, curr, { roles: curr.roles.some(o => o === 'Admin') }) acc.push(item) return acc }, []) console.log(result) // return true

or if it filter an array, my answer is the same as Tobias':)

Answer 3

  const array = [{
   "country": "all",
   "roles": [
    "Normal",
    "Admin",
   ]
   }]

    const val = array.map((a) => a.roles.includes('Admin'))
                  
    console.log(val) //return true