elseif 值小于获取值或大于

Question

I am trying to show echo 2 but its not working

$zipcode1 = 07300-011;
  $zipcode= str_replace("-","",$zipcode1);
$zipcode = 07300011;
   if ($zipcode >= 20000000 && $zipcode <= 26600999) { 
     echo '1';
}
   elseif ($zipcode >= 07000001 && $zipcode <= 07399999) { 

     echo '2';
}
else {
    echo 'no value';
    }
    

Please let me know where i am doing wrong. Thank you for the help Result = 2

Answer 1

You need to compare string with string if the leading 0 of the zipcode is important:

$zipcode1 = "07300-011";
$zipcode= str_replace("-","",$zipcode1);
$zipcode = "07300011";
if ($zipcode >= "20000000" && $zipcode <= "26600999") { 
    echo '1';
} elseif ($zipcode >= "07000001" && $zipcode <= "07399999") { 
    echo '2';
} else {
    echo 'no value';
}

Answer 2

You made two mistakes.

One is that the value assigned to $zipcode1 is not a string, but rather the result of an arithmetic operation. I'm saying $zipcode1 is not "07300-011" , but rather 07300-011 , which is equal to the octal number 7300 ( 3776 in base 10) minus octal 11 ( 9 in base 10), ie 3776 - 9 which is 3767 .

The second is that you're trying to do a numeric comparison using strings. "20" > "1000" is not the same as 20 > 1000 . The first would resolve to true , whereas the second would give false (which is likely what you want). To fix this, you have to first convert both of them to numbers. You can either cast them:

((int) $zipcode1) > (int) $zipcode2

or you can use the + sign instead:

(+$zipcode1) > (+$zipcode2)

In both cases, you need to first remove whitespaces and every other non-numeric character from the zipcode.

$zipcode = str_replace([' ', '-'], '', $zipcode);

Read the following topics in the php docs for more info:

1. Numeric Strings
2. Comparison Operators