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Oracle左外连接查询

[英]Oracle left outer join query

select a,last_note_user,c,d,iso_src
from X,Y,Z
left outer join W
ON (W.last_note_user=Z.userid AND W.user_ten=Y.iso_src)

when I am executing the above query it is giving me the error "Y.iso_src" is a invalid identifier .However, Y.iso_src is a valid identifier and it exist in the system table. 当我执行上面的查询时,它给出了错误"Y.iso_src" is a invalid identifier但是, Y.iso_src是一个有效的标识符,它存在于系统表中。 Is something wrong with the above left outer join?? 上面的左外连接有问题吗? Please help me out!!! 请帮帮我!!!

You cannot mix JOIN syntaxes in Oracle this way. 您不能以这种方式在Oracle混合使用JOIN语法。

A JOIN condition can only refer tables previously joined using ANSI JOIN syntax. JOIN条件只能引用先前使用ANSI JOIN语法连接的表。

Use this: 用这个:

SELECT  a, last_note_user, c, d, iso_src
FROM    X
CROSS JOIN
        Y
CROSS JOIN
        Z
LEFT OUTER JOIN
        W
ON      W.last_note_user = Z.userid
        AND W.user_ten = Y.iso_src

It's probably a good habit to not mix ANSI and non-ANSI join syntax as the other responses indicate. 如其他响应所示,不混合ANSI和非ANSI连接语法可能是一个好习惯。 However, it is technically possible, by isolating the non-ANSI joins into a subquery: 但是,通过将非ANSI连接隔离到子查询中,技术上是可行的:

create table X as (select dummy a, dummy c, dummy d from dual);

create table Y as (select dummy iso_src from dual);

create table Z as (select dummy userid from dual);

create table W as (select dummy last_note_user, dummy user_ten from dual);

select a,last_note_user,c,d,iso_src
from (select a, c, d, iso_src, userid FROM X,Y,Z) xyz
left outer join W
ON (W.last_note_user=xyz.userid AND W.user_ten=xyz.iso_src);

A LAST_NOTE_USER C D ISO_SRC 
- -------------- - - ------- 
X X              X X X       

1 rows selected

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