[英]how to check if a value in a column exists in same column multiple times in a pandas dataframe
My problem statement is that I want to check if a value in a column in a pandas data frame occurs for multiple times or not.我的问题陈述是我想检查熊猫数据框中的列中的值是否多次出现。 How can that be done?怎么可能呢? I am thinking of applying two for loops and something like this to search for multiple occurrences.我正在考虑应用两个 for 循环和类似的东西来搜索多个事件。 But this is showing an error:但这显示了一个错误:
for i in range(df_containing_nft.size):
Text_to_search=df_containing_nft.iat[i,0]
for j in range(i+1, df_containing_nft.size):
if (df_containing_nft.iat[j,0]==Text_to_search):
print(Text_to_search)
The error is the following:错误如下:
IndexError Traceback (most recent call last)
C:\Users\KESABC~1\AppData\Local\Temp/ipykernel_17020/3015476165.py in <module>
2 Text_to_search=df_containing_nft.iat[i,0]
3 for j in range(i, df_containing_nft.size):
----> 4 if (df_containing_nft.iat[j,0]==Text_to_search):
5 print(Text_to_search)
~\anaconda3\lib\site-packages\pandas\core\indexing.py in __getitem__(self, key)
2220
2221 key = self._convert_key(key)
-> 2222 return self.obj._get_value(*key, takeable=self._takeable)
2223
2224 def __setitem__(self, key, value):
~\anaconda3\lib\site-packages\pandas\core\frame.py in _get_value(self, index, col, takeable)
3564 if takeable:
3565 series = self._ixs(col, axis=1)
-> 3566 return series._values[index]
3567
3568 series = self._get_item_cache(col)
IndexError: index 91 is out of bounds for axis 0 with size 91
df.size
returns the number of value in the whole DataFrame. df.size
返回整个 DataFrame 中值的数量。 Since you only want to loop through index, you may want由于您只想遍历索引,因此您可能想要
for i in range(df_containing_nft.shape[0]): # or len(df_containing_nft)
Text_to_search=df_containing_nft.iat[i,0]
for j in range(i+1, df_containing_nft.shape[0]):
if (df_containing_nft.iat[j,0]==Text_to_search):
print(Text_to_search)
I guess what you want to do is我想你想做的是
df_containing_nft[df_containing_nft['col'].duplicated(), 'col'].tolist()
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