给定字符串使用正则表达式从字符串中过滤出唯一元素

Question

I have this String and I want to filter the digit that came after the big number with the space, so in this case I want to filter out 2 and 0.32. I used this regex below which only filters out decimal numbers, however I want to filter both decimals and integer numbers, is there any way?

String s = "ABB123,ABPP,ADFG0/AA/BHJ.S,392483492389 2,BBBB,YUIO,BUYGH/AA/BHJ.S,3232489880 0.32"

regex = .AA/BHJ.S,\d+ (\d+.?\d+)

https://regex101.com/r/ZqHDQ8/1

Answer 1

The problem is that \d+.?\d+ matches at least two digits. \d+ matches one or more digits, then .? matches any optional char other than line break char, and then again \d+ matches (requires) at least one digit (it matches one or more).

Also, note that all literal dots must be escaped.

You can use

.AA/BHJ\.S,\d+\s+(\d+(?:\.\d+)?)

See the regex demo .

Details :

• . - any one char
• AA/BHJ\.S, - a AA/BHJ.S, string
• \d+ - one or more digits
• \s+ - one or more whitespaces
• (\d+(?:\.\d+)?) - Group 1: one or more digits, and then an optional sequence of a dot and one or more digits.

Answer 2

You could look for anything following /AA/BHJ with a reluctant quantifier, then use a capturing group to look for either digits or one or more digits followed by a decimal separator and other digits.

/AA/BHJ.*?\s+(\d+\.\d+|\d+)

Here is a link to test the regex:

https://regex101.com/r/l5nMrD/1