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路径 url split() find() 角度

[英]path url split() find() angular

I have urls and I want to recover the beginning of the path but I don't know how to do it and being a beginner according to my research I should use the split() and find() method.我有 url,我想恢复路径的开头,但我不知道该怎么做,根据我的研究,作为初学者,我应该使用 split() 和 find() 方法。

Here are the urls:以下是网址:

/test/someurls /test/someurls

/angular/someurls /角/someurls

I need to get /test and /angular is it possible to do that?我需要获取/test/angular是否可以这样做?

Thanks in advance.提前致谢。

ngOnInit() {

 let firstUrl: string = '/test/someurls';
 let secondUrl:string = '/angular/someurls';

 let t = firstUrl.split(" ").find(element =>element.startWith('/test');
    console.log(t);
}

Here is code using split function.这是使用拆分功能的代码。

function getBeginning(a) {
  return "/" + a.split("/")[1];
}
console.log(getBeginning("/test/some"));
console.log(getBeginning("/angular/some"));

Another interesting way with Angular api: Angular api 的另一种有趣方式:

const urlTree = this.router.parseUrl('/angular/someurls');


...
getBeginningFromUrlTree(urlTree: UrlTree): string {
  return `/${urlTree.root.children.primary.segments[0].path}`;
}

crumbs = this.router.url.split('/');

constructor(private router: Router) {}

Something like this ?像这样的东西?

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