检查javascript / typescript中两个对象数组中的相同名称？

Question

I have two array of objects

array1=[{name:'apple',deleted:false},
       {name:'road',deleted:false},
       {name:'tree',deleted:false}]

and

array2=[{name:'apple'},
       {name:'tree'}]

what I want is : if array1 object has same names in array2, I want to change value of "deleted" in array1 to true . eg : {name:'apple',deleted:true}

expecting resulting array1:

array1=[{name:'apple',deleted:true},
           {name:'road',deleted:false},
           {name:'tree',deleted:true}]

here you can see , only apple, tree has deleted=true , because array2 has only 2 names : apple and tree .

Answer 1

you can :

• loop on array1 with forEach for sample

• use some function to set deleted boolean

  deleted = array2.some(elem2 => elem2.name === elem.name) 

 const array1 = [{ name: 'apple', deleted: false }, { name: 'road', deleted: false }, { name: 'tree', deleted: false } ] const array2 = [{ name: 'apple' }, { name: 'tree' } ]; array1.forEach(elem => elem.deleted = array2.some(elem2 => elem2.name === elem.name)); console.log(array1);

Answer 2

Use forEach() to loop array1 and use include() to set value of deleted

 const array1=[{name:'apple',deleted:false}, {name:'road',deleted:false}, {name:'tree',deleted:false}] const array2=[{name:'apple'}, {name:'tree'}] array1.forEach(el=> el.deleted = array2.map(foo => foo.name).includes(el.name)) console.log(array1)

Answer 3

1. Create a Set of deletedItems .

2. Map over the items and update the deleted property using the Set .

 const items = [{ name: "apple", deleted: false }, { name: "road", deleted: false }, { name: "tree", deleted: false }], deletedItems = [{ name: "apple" }, { name: "tree" }], deletedSet = new Set(deletedItems.map((d) => d.name)), updatedItems = items.map((i) => (deletedSet.has(i.name) ? { ...i, deleted: true } : i)); console.log(updatedItems);

Answer 4

You can use Array.map and Array.find :

 let array1=[ {name:'apple',deleted:false}, {name:'road',deleted:false}, {name:'tree',deleted:false} ]; let array2=[ {name:'apple'}, {name:'tree'} ]; array1 = array1.map(item1 => array2.find(item2 => item1.name == item2.name) ? {...item1, deleted:true} : item1); console.log(array1)