[英]How to treat a float as an integer bit level in AssemblyScript
I need to implement some C code blow:我需要实现一些 C 代码打击:
float number = 1.5f
long i = * ( long * ) &number;
It is not about to convert the value from float into integer.它不会将值从浮点数转换为整数。 This data need to be modified bit level.
此数据需要修改位级别。
Just use reinterpret
built-in function:只需使用
reinterpret
内置函数:
let num32: f32 = 1.5
let num64: f64 = 2.5
let uint32 = reinterpret<u32>(num32);
// uint32 <- 0x3fc00000
let uint64 = reinterpret<u64>(num64);
// uint64 <- 0x4004000000000000
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