转储时如何对 JSON 值进行排序？

Question

I am trying to dump/sort JSON values by a specific time format.

Before asking, I have looked as various questions such as:

1. When I tried to sort a list, I got an error 'dict' object has no attribute (This was actually a problem after trying some things)
2. Sorting a JSON file by a certain key (Most specific one, though I do not use any name keys)
3. JSON output sorting in Python (Did not really help)

The structure of my JSON is the following:

{
  "Arthur": "12/12",
  "Lisa": "10/12"
}

The date format is dd/mm . I want to have 10/12 before 12/12 in that matter. This should not however happen while reading out the JSON, but rather while dumping the value.

The codes I tried to use:

with open(f"saved_date.json", "r", encoding='utf-8') as f:
    data = json.load(f) # Just so you can see how I read out the JSON


with open('saved_date.json', 'w', encoding='utf-8') as fpp:
    json.dump(data, fpp, indent=2, sort_keys=True) # Sorting the keys does not work obviously

with open('saved_date.json', 'w', encoding='utf-8') as fpp:
    json.dump(sorted(data, key=lambda x: datetime.strptime(date, "%d/%m")), fpp, indent=2) # date is individually given in the format mentioned above 

Maybe someone here can see what went wrong or give me tips on how to better structure it. I currently update the JSON with:

        try:
            data[f"{author}"] = date # author is the one using/executing the code
        except:
            new = {author: date}
            data.update(new)

Answer 1

Because your dates are in dd/mm format, you cannot sort them alphabetically; you need instead to sort on the mm part, then the dd part:

data = {'Arthur': '12/12', 'Lisa': '10/12', 'Joe': '31/05'}

json.dumps(dict(sorted(data.items(), key=lambda x: x[1].split('/')[::-1])), indent=2)

Output:

{
  "Joe": "31/05",
  "Lisa": "10/12",
  "Arthur": "12/12"
}

Answer 2

data = {'Arthur': '12/12', 'Lisa': '10/12'}

with open('saved_date.json', 'w', encoding='utf-8') as f:
    json.dump(dict(sorted(data.items(), key=lambda x: x[1])), f, indent=2)

Output:

{
  "Lisa": "10/12",
  "Arthur": "12/12"
}