如何在节点模块中获取当前模块的文件路径？

Question

I want to print the correct filepath even if the function is imported in some other module inorder to handle the errors correctly. How can I do that? I am using serverless stack.

Please refer the following code,

 class Logger { filePath: string; constructor(fp: string) { filePath = fp; } printLog(info) { const { timestamp, message } = info; return `${timestamp} ${filePath}: ${message}`; } }

This is used in dbConnection.ts as,

 const logger = new Logger(__filename); export const connectToDB = () => { try { //DB connection code. } catch(error) { logger.print({ timestamp: new Date().toISOString(), message: error.message }); } };

Now, I want to connect to db from some other module lets say, test.ts then I will use it as follows,

 export const test = () => { //some code here... connectToDB(); }

When there occurs an error while connecting to DB, then It prints something like this,

2022-05-27T05:24:47.548Z src/test.ts: Error in connecting DB url is unreachable please check your inte.net connection.

In order to have proper debuggability, I want to print the filename from where the exception is actually thrown. That is src/dbConnection.ts and not src/test.ts .

Answer 1

Try using

__filename

__filename : This will return the path of the file executing

__dirname : This will return the path of the directory in which the file executing is located.

Check if it does what you need like

console.log(__filename);

Answer 2

Try to change filePath to this.filePath in your Logger Class