我如何在 python 的 while 循环中逐行打印 a.txt 文件中的每一行

Question

Ok so, lets say i have data from a.txt file here:

ToddShields74

GeorgeGutierrez18

ReginaHenry71

JohnBlair34

PaigeKirby47

...

Now, i want a python code that will print each line one by one in a loop, for example:

while/if (imagine some random thing here):
print(line1 of the text file)

(obviously not a real code but presenting what i need.)

Then the next loop should print the next line, and the next, until it has printed all the lines in the file

Help is really appreciated!

Answer 1

You can simply open the file and iterate through it:

file_name = "file.txt"

with open(file_name) as f:
    for line in f:
        print(line.strip()) # strip to remove extra newline after each line
        # whatever else you want to do

Answer 2

You can use a regular expression and sort it by the new line \n character

import re

txt = your text here
x = re.findall(".+\n", txt)

The .+ will get anything that comes before a new line, \n.

This will return a list of all matches seperated by line and you can loop through them.