如何通过解析转义字符串在 Haskell 中组成未转义的 Unicode 字符串？
[英]How do you compose an unescaped Unicode string in Haskell by parsing the escaped string?
问题描述
I am parsing some text which might be "\㈀".<\/i>
我正在解析一些可能是“\㈀”的文本。<\/b> Parsing this and converting to decimal, I know the integer sequence should be 12800. Now, I want to put this back together;<\/i>解析这个并转换成十进制，我知道整数序列应该是 12800。现在，我想把它放回去；<\/b> I might do the following:<\/i>我可能会做以下事情：<\/b><\/p>
toPrintedChar x = return "\\x" ++ x
1 个解决方案
解决方案1
1 已采纳 2022-05-30 07:05:28
To convert an integer value into a string made of that Unicode code point, it is enough to convert the number into a Char and then put it in a list.要将整数值转换为由该 Unicode 代码点组成的字符串，只需将数字转换为Char ，然后将其放入列表中即可。 Eg,例如，
myString :: String
myString = [ toEnum 12800 ]
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