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为什么我会清理基于文件的变量 00:01 错误：作业失败：gitlab 管道创建中的退出代码 1

[英]why im getting Cleaning up file based variables 00:01 ERROR: Job failed: exit code 1 in gitlab pipeline creation

原文 2022-05-30 12:27:31 4 1 gitlab/ yaml/ pipeline

commit-message-validator: stage: validate-commit-message script: - echo "$CI_COMMIT_MESSAGE" - echo "$CI_COMMIT_BRANCH" - echo "check the Prefix of the commit message should have one of 'fix' || 'feat' || 'major' || 'minor' in case sensitive" - exit 1 commit-message-validator: stage: validate-commit-message script: - echo "$CI_COMMIT_MESSAGE" - echo "$CI_COMMIT_BRANCH" - echo "检查提交消息的前缀应该是 'fix' || 'feat' | | 'major' || 'minor' 区分大小写" - 出口 1

rules: - if: $CI_COMMIT_MESSAGE =~ /fix: / when: never - if: $CI_COMMIT_MESSAGE =~ /feat: / when: never - if: $CI_COMMIT_MESSAGE =~ /major: / when: never - if: $CI_COMMIT_MESSAGE =~ /minor: / when: never - if: "$CI_COMMIT_MESSAGE =~ /^chore$release$:.*/" when: never - if: $CI_COMMIT_BRANCH == $CI_DEFAULT_BRANCH when: never - when: always规则： - if: $CI_COMMIT_MESSAGE =~ /fix: / when: never - if: $CI_COMMIT_MESSAGE =~ /feat: / when: never - if: $CI_COMMIT_MESSAGE =~ /major: / when: never - if: $CI_COMMIT_MESSAGE = ~ /minor: / when: never - if: "$CI_COMMIT_MESSAGE =~ /^chore$release$:.*/" when: never - if: $CI_COMMIT_BRANCH == $CI_DEFAULT_BRANCH when: never - when: always

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1 个解决方案

The last step in your script block is exit 1 . script块中的最后一步是exit 1 。 Gitlab CI will fail any job that has an exit code > 0. Gitlab CI 将失败任何退出代码 > 0 的作业。

The commit-message-validator job doesn't currently do any checks, it simply calls echo 3 times. commit-message-validator作业目前不做任何检查，它只是调用echo 3 次。 If you want it to check for fix, feat, major, minor you will need to do write some logic in the script block to do so.如果您希望它检查fix, feat, major, minor您需要在script块中编写一些逻辑来执行此操作。