如何将多个函数名称解析为 python 命令行参数？

Question

I have few methods in a class, and I want to allow the user to run their desired methods only by parsing the method name, but I'm stuck at the argparser code, would like to ask for advices here

Basically I want to accomplish something like below

python3 test.py -ip 10.10.10.100 -op method1 method2 method3 ...

in my code

class myClass(parentClass):
    def __init__(self) -> None:
        """
        Setup target system
        """
        try:
            super().__init__()

            self.parser = argparse.ArgumentParser()
            self.parser.add_argument('-ip', help='IP address of target system')
            self.parser.add_argument('-op', help='User desired options')
            self.args, unknown = self.parser.parse_known_args()
        except Exception as exp:
            print(f'Error: {exp}')
    
    def method1(self):
        pass

    def method2(self):
        pass

    def run_prog(self):
        # append user desired method into a list?
        # loop through the list and execute each method
        for i in the_list:
            fn = getattr(self, i)
            fn()

*I have to put argparse in __init__ to follow my org standardization

Answer 1

在声明-op参数解析器时添加nargs='+'选项怎么样？

self.parser.add_argument('-op', help='User desired options', nargs='+')