[英]C++ type for functor structs
I am trying to have a single variable with some type that can be assigned to some of the C++ standard functors (eg: std::plus
, std::multiplies
, etc...)我正在尝试使用可以分配给某些 C++ 标准函子的某种类型的单个变量(例如: std::plus
、 std::multiplies
等...)
Here is the definition for std::plus
(from this link ):这是std::plus
的定义(来自此链接):
template <class T> struct plus : binary_function <T,T,T> {
T operator() (const T& x, const T& y) const {return x+y;}
};
I tried我试过了
#include <functional>
std::binary_function<int, int, int> func = std::plus;
but it doesn't work.但它不起作用。 How do I define it properly?如何正确定义它?
A single variable to hold all kinds of callables with same signature is std::function<int(int,int)>
.保存具有相同签名的各种可调用对象的单个变量是std::function<int(int,int)>
。 Though the functors need to either have the template argument specified or deducde them from arguments:尽管仿函数需要指定模板参数或从参数中推断出它们:
std::function<int(int,int)> func2 = [](int a,int b){ return std::plus{}(a,b);};
or或者
std::function<int(int,int)> func = std::plus<int>{};
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