从表中选择特定 ID 的最新条目

Question

I have the following table

Report Number	Department	Date	Price
77e1117e-a248-4781-866f-704bea114d11	Dep. 01	2022-06-13 10:12:42.000	685.10
77e1117e-a248-4781-866f-704bea114d11	Dep. 01	2022-06-13 10:12:42.000	0.19
a34f8425-c64f-47a9-b947-49e7d2fd5bba	Dep. 01	2022-06-13 13:16:45.000	102.45
a34f8425-c64f-47a9-b947-49e7d2fd5bba	Dep. 01	2022-06-13 13:16:45.000	427.13
h94e8421-h79j-25q9-n478-58w7f2af6ffe	Dep.02	2022-06-13 13:16:45.000	98.98
h94e8421-h79j-25q9-n478-58w7f2af6ffe	Dep. 02	2022-06-13 13:16:45.000	500.50

These are two reports, each with two entries, generated at a different time and yielding a different price.

I would like to have a script/code that can automatically choose the latest date and return the sum of prices corresponding to that report number per department.

The output should be something like that:

Report Number	Department	Date	Price
a34f8425-c64f-47a9-b947-49e7d2fd5bba	Dep. 01	2022-06-13 13:16:45.000	529.58
h94e8421-h79j-25q9-n478-58w7f2af6ffe	Dep. 02	2022-06-13 13:16:45.000	599.48

Answer 1

Select ReviewNr, [Date], Sum(Price)
from myTable
where ReviewNr in (select top(1) reviewNr from myTable order by [Date] desc)
group by ReviewNr, [Date]; 

DBFiddle demo

Answer 2

Something like this:

SELECT *
FROM (
    SELECT *,
        ROW_NUMBER() OVER (PARTITION BY ProductId ORDER BY Date DESC ) AS RowNumber,
        SUM(Price) OVER (PARTITION BY ProductId ) PriceSum
    FROM WhateverTableItIs
) T
WHERE RowNumber = 1

(Why have you posted HTML when your question is about SQL?!)

Answer 3

Seems like you can aggregate the rows for each ReportNumber then use ROW_NUMBER by date

SELECT
  Department,
  ReportNumber,
  Date,
  Price
FROM (
    SELECT
      Department,
      ReportNumber,
      Date,
      SUM(Price) Price,
      ROW_NUMBER() OVER (PARTITION BY Department ORDER BY Date DESC) rn
    FROM YourTable t
    GROUP BY
      Department,
      Date,
      ReportNumber
) t
WHERE rn = 1;

db<>fiddle