通过深层嵌套数组对象中的特定键查找所有子键

Question

const data = [
  {
    title: '0-0',
    key: '0-0',
    children: [
      {
        title: '0-0-0',
        key: '0-0-0',
        children: [
          { title: '0-0-0-0', key: '0-0-0-0' },
          { title: '0-0-0-1', key: '0-0-0-1' },
          { title: '0-0-0-2', key: '0-0-0-2' },
        ],
      },
      {
        title: '0-0-1',
        key: '0-0-1',
        children: [
          { title: '0-0-1-0', key: '0-0-1-0' },
          { title: '0-0-1-1', key: '0-0-1-1' },
          { title: '0-0-1-2', key: '0-0-1-2' },
        ],
      },
      {
        title: '0-0-2',
        key: '0-0-2',
      },
    ],
  },
  {
    title: '0-1',
    key: '0-1',
    children: [
      { title: '0-1-0-0', key: '0-1-0-0' },
      { title: '0-1-0-1', key: '0-1-0-1' },
      { title: '0-1-0-2', key: '0-1-0-2' },
    ],
  },
  {
    title: '0-2',
    key: '0-2',
  },
];

How would I get an array of all values throughout all nests of this obj by the key of id.

For example

input: ["0-0-0"]

i wanna output like this

output: ["0-0-0", "0-0-0-0", "0-0-0-1", "0-0-0-2"]

enter image description here

Answer 1

You can recursively loop over all the children and get the keys that either match one of the target keys or if any of their ancestors have matched one the target keys.

 const data = [ { title: "0-0", key: "0-0", children: [ { title: "0-0-0", key: "0-0-0", children: [ { title: "0-0-0-0", key: "0-0-0-0" }, { title: "0-0-0-1", key: "0-0-0-1" }, { title: "0-0-0-2", key: "0-0-0-2" }, ], }, { title: "0-0-1", key: "0-0-1", children: [ { title: "0-0-1-0", key: "0-0-1-0" }, { title: "0-0-1-1", key: "0-0-1-1" }, { title: "0-0-1-2", key: "0-0-1-2" }, ], }, { title: "0-0-2", key: "0-0-2", }, ], }, { title: "0-1", key: "0-1", children: [ { title: "0-1-0-0", key: "0-1-0-0" }, { title: "0-1-0-1", key: "0-1-0-1" }, { title: "0-1-0-2", key: "0-1-0-2" }, ], }, { title: "0-2", key: "0-2", }, ]; function getKeys(data, targetKeys) { const targetKeysSet = new Set(targetKeys); const outputKeys = []; function getKeysHelper(data, hasParentMatched = false) { data?.forEach((d) => { if (targetKeysSet.has(d.key) || hasParentMatched) { outputKeys.push(d.key); getKeysHelper(d.children, true); } else { getKeysHelper(d.children); } }); } getKeysHelper(data); return outputKeys; } getKeys(data, ["0-0-0"]);

Relevant documentations:

• Optional chaining (?.)
• Array.prototype.includes
• Set

Answer 2

you can do something like this

 const extractKeys = data => { const loop = (data, res) => { if(!data.children){ return [...res, data.key] } return data.children.flatMap(d => loop(d, [...res, data.key])) } return [...new Set(loop(data, []))] } const findKeys = (data, keys) => data.flatMap(extractKeys).filter(k => keys.some(key => k.includes(key))) const data = [ { title: '0-0', key: '0-0', children: [ { title: '0-0-0', key: '0-0-0', children: [ { title: '0-0-0-0', key: '0-0-0-0' }, { title: '0-0-0-1', key: '0-0-0-1' }, { title: '0-0-0-2', key: '0-0-0-2' }, ], }, { title: '0-0-1', key: '0-0-1', children: [ { title: '0-0-1-0', key: '0-0-1-0' }, { title: '0-0-1-1', key: '0-0-1-1' }, { title: '0-0-1-2', key: '0-0-1-2' }, ], }, { title: '0-0-2', key: '0-0-2', }, ], }, { title: '0-1', key: '0-1', children: [ { title: '0-1-0-0', key: '0-1-0-0' }, { title: '0-1-0-1', key: '0-1-0-1' }, { title: '0-1-0-2', key: '0-1-0-2' }, ], }, { title: '0-2', key: '0-2', }, ]; console.log(findKeys(data, ['0-0-0']))