使用 webbrowser.open 按顺序打开多个网页

Question

So what i want to do is very simple. I have a list of words and for each word in the list i want to open three websites. Like website 1: word 1,website 2: word 1,website 3: word 1,website 1: word 2, ... . My attempt to do so was as fallow:

import webbrowser

wordList = ["word1", "word2", "word3",]

for word in wordList:
    url = "https://www.ldoceonline.com/dictionary/" + word
    webbrowser.open(url, new=2, autoraise=False)
    url = "https://dictionary.cambridge.org/dictionary/english/" + word
    webbrowser.open(url, new=2, autoraise=False)
    url = "https://www.google.com/search?q=" + word
    webbrowser.open(url, new=2, autoraise=False)

The problem is when the list is long then the websites do not open in order. Is there a way to make sure they open in correct order?

I use Firefox as default browser and my OS is windows.

Answer 1

It seems that the URLs are being opened too fast. If the main focus is that they should be in order, then I would suggest the following code:

import webbrowser
import time

LOAD_TIME = 0.2 # s

word_list = ["word1", "word2", "word3",]
url_list = ["https://www.ldoceonline.com/dictionary/", "https://dictionary.cambridge.org/dictionary/english/", "https://www.google.com/search?q="]

for word, url in zip(word_list, url_list):
    status = webbrowser.open(url+word, new=2, autoraise=False)
    time.sleep(LOAD_TIME)

It just gives the script some time before moving on to the next open() exicution.

The looping through the combined variables is set up with a cleaner zip , and you can test the variable LOAD_TIME a few times. You might need a longer or shorter load time interval depending on your machine, internet speed, etc. If speed is not a concern but the order of the tabs is most important, you can set this variable to be quite high.

EDIT: If you want to avoid the time module, the following also worked for me:

import webbrowser

word_list = ["word1", "word2", "word3",]
url_list = ["https://www.ldoceonline.com/dictionary/", "https://dictionary.cambridge.org/dictionary/english/", "https://www.google.com/search?q="]

for word, url in zip(word_list, url_list):
    if webbrowser.open(url+word, new=2, autoraise=False):
        continue

Explanation: The code waits for a response of True or False from the current webbrowser.open() call before moving on to the next.

EDIT2: If you want to open each word in all three links, then the zip function is not the one. You might want a double-for loop instead. If you want the order in which the links are opened to be (url1+word1), (url2+word1), (url3+word1), (url1+word2), ... , then the double for loop would look like:

import webbrowser

word_list = ["word1", "word2", "word3",]
url_list = ["https://www.ldoceonline.com/dictionary/", "https://dictionary.cambridge.org/dictionary/english/", "https://www.google.com/search?q="]

for word in word_list:
    for url in url_list:
        if webbrowser.open(url+word, new=2, autoraise=False):
            continue