Python 字典累计值转个体值

Question

Now I have a Python dictionary my_dict:

level_1	level_2	level_3	level_4	level_5
2	2	8	11	13

my_dict = {'level_1':2, 'level_2':2, 'level_3':8, 'level_4':11, 'level_5':13}

The value of the dictionary now is accumulative, I am wondering how to get the python dictionary with individual value:

level_1	level_2	level_3	level_4	level_5
2	0	6	3	2

Thanks in advance for any helps!

Answer 1

You can use pandas for that, especially if your data grows for many columns:

df = pd.DataFrame(my_dict, index=[0])
df.diff(axis=1).fillna(df)

Without pandas, you may use a simple dict comprehension:

{k: my_dict.get(f'level_{int(k[-1])}', 0) - \
    my_dict.get(f'level_{int(k[-1]) - 1}', 0) \
    for k in my_dict.keys()}