是否可以使用 bash cmd 获取 file1 减去 file2 的内容？

Question

I have two files:

log.txt 
log.bak2022.06.20.10.00.txt

the log.bak2022.06.20.10.00.txt is the backup of log.txt at 2022.06.20 10:00 .

but the log.txt is a content-increasing file.

now I have a requirement, I want get the content of log.txt minus log.bak2022.06.20.10.00.txt , then write into a new file. is it possible to implement it?

Answer 1

Assumptions:

• the small file contains N lines, and these N lines are an exact match for the 1st N lines in the big file

Sample inputs:

$ cat small
4
2
1
3

$ cat big
4
2
1
3
8
10
9
4

One comm idea:

$ comm --nocheck-order -13 small big
8
10
9
4

One awk idea:

$ awk '
FNR==NR { max=FNR; next }
FNR>max
' small big
8
10
9
4

One wc/sed idea:

$ max=$(wc -l < small)
$ ((max++))
$ sed -n "$max,$ p" big
8
10
9
4

Answer 2

awk -based solution without need for unix piping | chains, regex , function calling, or array splitting :

{m,n,g}awk '(_+= NR==FNR ) < FNR' FS='^$' small.txt big.txt 

8
10
9
4