使用正则表达式提取字符串后跟带有空格的数字

Question

I have the follwing string

[1] weight | width | depth | 5.0 kg | 6.0 mm^3 | 10.12 cm^2

From that I need to extract the unit strings only

unit=kg
unit=mm^3
unit=cm^2

I tried the below regex

(?<unit>[^ -+0-9\\.\|\[\}\]]+)

But it is also giving the weight,width,depth values too. Also tried

(?<unit>[\D][^|]+)

but not worked. I think I need to extract the strings which are followed by number and space

Can you help me on this

Answer 1

You could use a character class to list the allowed characters:

\b[0-9]+(?:\.[0-9]+)?[^\S\r\n]+(?<unit>[a-z^0-9]+)\b

Regex demo

Or more specific:

\b[0-9]+(?:\.[0-9]+)?[^\S\r\n]+(?<unit>kg|[mc]m)\b

See another regex demo

If there should be either a pipe or the end of the string:

\b[0-9]+(?:\.[0-9]+)?[^\S\r\n]+(?<unit>[^0-9\s]\S*)(?:[^\S\r\n]+\||$)

Regex demo

Answer 2

I have used below regex, and it is matching only unit string.

 \b[a-z]{2}(?:[\^]\d+)?(?!\S)\b

Demo link : https://regex101.com/r/AjONqR/1