对不可迭代实例的解构尝试无效。 为了可迭代，非数组对象必须有一个 [Symbol.iterator]() 方法

Question

i'm using react native with regex

if i use my code

this error occured

Invalid attempt to destructure non-iterable instance. In order to be iterable, non-array objects must have a Symbol.iterator method.

I want to put an empty value like ' ' in the match if any character other than a number and decimal point is included in my regular expression. If you put "123abc" in the value variable, match returns "123", but if you put "acv" in the value constant, the above error occurs. In this case, how can I put an empty string into the match without generating an error?

 const regex = /\d+(\.\d{1,2})?/;

const value = "abd"
const [match] = regex.exec(value);

Answer 1

you can use || operator. in case exec return null it will default to empty string '' .

 function getStrings(value) { const regex = /\d+(\.\d{1,2})?/; const [match] = [regex.exec(value) || '']; if(Array.isArray(match)) return match[0] return match } console.log(getStrings("abd")) console.log(getStrings("123abd"))