如何在特定索引之后获取列表索引

Question

If I have the list: ['a', 'b', 'c', 'd', 'e'] , and I want a variable like this: afterC = ['d','e'] - Aka, all items after 'c' get put into their own list. I've tried searching for a solution, but I can't find anything

Answer 1

The list object has an .index() method which returns the index of a given value. This index can be used to slice the list and return the values after the given index.

For example:

l = ['a', 'b', 'c', 'd', 'e']

l2 = l[l.index('c') + 1:]

Output:

>>> l2
['d', 'e']

Documentation linked here