[英]XML/XPath: Distinguish equal nodes via siblings
I have an XML of the following form:我有以下形式的 XML:
<A>
<B>
<C/> <!-- Want to find ONLY this C -->
</B>
<B>
<D/>
<C/>
</B>
</A>
Is there a way of only finding the element C which has no preceding-sibling?有没有办法只找到没有前兄弟的元素C ? I was looking into XPath and XPathAxes , but did not come up with a solution... Does anyone know if there is a way with Xpath-syntax to achieve this?
我正在研究XPath和XPathAxes ,但没有想出一个解决方案......有谁知道是否有办法使用 Xpath-syntax 来实现这一点?
基本上就是你所说的: //C[not(preceding-sibling::*)]
。
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