正则表达式忽略引号中的字符

Question

Is there a way to ignore text between certain characters? My current regular expression is including text between quotes. I need this to be ignored.

raw_pmc_df\[\'(.*?)]

Current Output:

to_max(((100 * **raw_pmc_df['CPF_CPF_STAT_STALL']**) / **raw_pmc_df['CPF_CPF_STAT_BUSY']**).where((**raw_pmc_df['CPF_CPF_STAT_BUSY']** != 0), None))

Desired Output:

to_max(((100 * **raw_pmc_df['** CPF_CPF_STAT_STALL **']**) / **raw_pmc_df['** CPF_CPF_STAT_BUSY **']**).where((**raw_pmc_df['** CPF_CPF_STAT_BUSY **']** != 0), None))

Answer 1

One idea is to use positive lookahead:

raw_pmc_df(?=\['[^']+'\])

The match will be

raw_pmc_df

You can add the square brackets afterwards.

There is no way to have split matches in common regex engines. In fact there is no need to: you design a regex with multiple capture groups:

(raw_pmc_df)(\[)(?:'[^']'+)(\])

The desired result is the concatenation of capture groups 1, 2, 3 (the quotes part does not count because of the (: parentheses). This way you do not need a positive lookahead.

In this particular example the regex is contrived as capture groups 2 and 3 contain strings known in advance.

Answer 2

It seems you want to remove these raw and [' with '] , and keep the contents that are in between.

If this is the case, you can use

raw_pmc_df\[\'(.*?)']

and replace with $1 (or \1 , depending on your programming environment).

See the regex demo .

Details :

• raw_pmc_df\[\' - a raw_pmc_df[' string
• (.*?) - Group 1: any zero or more chars other than line break chars as few as possible
• '] - a '] string.