[英]Convert a flattened excel to nested json in pandas
I am fairly new to this and have spent the entire day reading numerous posts and figuring out how i can convert this flattened excel table to a nested json.我对此相当陌生,并且花了一整天的时间阅读大量帖子并弄清楚如何将这个扁平的 excel 表转换为嵌套的 json。 Here is an example of the flattened nested table:
以下是扁平嵌套表的示例:
{'Sample': {0: '1A',
1: '1A',
2: '1A',
3: '1A',
4: '1A',
5: '1A',
6: '1A',
7: '2A',
8: '2A',
9: '2A',
10: '2A',
11: '2A',
12: '2A',
13: '2A'},
'Substance category': {0: 'Additive',
1: 'Additive',
2: 'Alkali',
3: 'Alkali',
4: 'Alkali',
5: 'Alkali',
6: 'Alkali',
7: 'Additive',
8: 'Additive',
9: 'Alkali',
10: 'Alkali',
11: 'Alkali',
12: 'Alkali',
13: 'Alkali'},
'Substance': {0: 'Irgafos 168',
1: 'Alkylphenylphosphate',
2: 'Calcium',
3: 'Kalium',
4: 'Lithium',
5: 'Magnesium',
6: 'Natrium',
7: 'Irgafos 168',
8: 'Alkylphenylphosphate',
9: 'Calcium',
10: 'Kalium',
11: 'Lithium',
12: 'Magnesium',
13: 'Natrium'},
'Value': {0: 0,
1: 0,
2: 2,
3: 2,
4: 1,
5: 2,
6: 3,
7: 2,
8: 3,
9: 2,
10: 3,
11: 1,
12: 2,
13: 3}}
This table looks like this Sample table这个表看起来像这个示例表
I used the following code to get a nested json, which was taken from this answer .我使用下面的代码来获取一个嵌套的 json,它取自这个答案。
j = (df.groupby(['Sample','Substance category'])
.apply(lambda x: x[['Substance','Value']].to_dict('records'))
.reset_index()
.rename(columns={0:'Substance'})
.to_json(orient='records'))
I am getting the following json.我得到以下json。
[
{
"Sample": "1A",
"Substance": [
{
"Substance": "Irgafos 168",
"Value": 0
},
{
"Substance": "Alkylphenylphosphate",
"Value": 0
}
],
"Substance category": "Additive"
},
{
"Sample": "1A",
"Substance": [
{
"Substance": "Calcium",
"Value": 2
},
{
"Substance": "Kalium",
"Value": 2
},
{
"Substance": "Lithium",
"Value": 1
},
{
"Substance": "Magnesium",
"Value": 2
},
{
"Substance": "Natrium",
"Value": 3
}
],
"Substance category": "Alkali"
},
{
"Sample": "2A",
"Substance": [
{
"Substance": "Irgafos 168",
"Value": 2
},
{
"Substance": "Alkylphenylphosphate",
"Value": 3
}
],
"Substance category": "Additive"
},
{
"Sample": "2A",
"Substance": [
{
"Substance": "Calcium",
"Value": 2
},
{
"Substance": "Kalium",
"Value": 3
},
{
"Substance": "Lithium",
"Value": 1
},
{
"Substance": "Magnesium",
"Value": 2
},
{
"Substance": "Natrium",
"Value": 3
}
],
"Substance category": "Alkali"
}
]
However what I actually want is to define an addition level for the 'Substance category'.但是我真正想要的是为“物质类别”定义一个添加级别。 Despite all my efforts, I just could not figure that out and none of the answers could help me.
尽管我付出了所有努力,但我还是想不通,没有一个答案可以帮助我。
Thank you very much in advance.非常感谢您提前。
This would be my process:这将是我的过程:
to_json()
to_json()
从数据帧写入“json” so the code looks like this:所以代码看起来像这样:
#%%
import pandas as pd
d = {'Sample': {0: '1A',
1: '1A',
2: '1A',
3: '1A',
4: '1A',
5: '1A',
6: '1A',
7: '2A',
8: '2A',
9: '2A',
10: '2A',
11: '2A',
12: '2A',
13: '2A'},
'Substance category': {0: 'Additive',
1: 'Additive',
2: 'Alkali',
3: 'Alkali',
4: 'Alkali',
5: 'Alkali',
6: 'Alkali',
7: 'Additive',
8: 'Additive',
9: 'Alkali',
10: 'Alkali',
11: 'Alkali',
12: 'Alkali',
13: 'Alkali'},
'Substance': {0: 'Irgafos 168',
1: 'Alkylphenylphosphate',
2: 'Calcium',
3: 'Kalium',
4: 'Lithium',
5: 'Magnesium',
6: 'Natrium',
7: 'Irgafos 168',
8: 'Alkylphenylphosphate',
9: 'Calcium',
10: 'Kalium',
11: 'Lithium',
12: 'Magnesium',
13: 'Natrium'},
'Value': {0: 0,
1: 0,
2: 2,
3: 2,
4: 1,
5: 2,
6: 3,
7: 2,
8: 3,
9: 2,
10: 3,
11: 1,
12: 2,
13: 3}}
# make dataframe
df = pd.DataFrame(d)
# %% send to excel
json_path = "C:\\test\\test.json"
df.to_json(json_path)
The dataframe (before the json) looks like this:数据框(在 json 之前)如下所示:
You can manipulate the dataframe as you wish from here.您可以从这里随心所欲地操作数据框。
Are you asking to create a multilevel dataframe ?您是否要求创建多级数据框? if so, then the final part is answered here:
如果是这样,那么最后一部分在这里回答:
How to create a multilevel dataframe in pandas? 如何在熊猫中创建多级数据框?
Well creating a multilevel df was not a problem.那么创建多级df不是问题。 But when I exported that to a json, it did not maintain the nested structure of the indexes.
但是当我将它导出到 json 时,它并没有维护索引的嵌套结构。 Anyway, I finally found an answer here.
无论如何,我终于在这里找到了答案。 It was just a matter to searching on google with the right keywords link
用正确的关键字链接在谷歌上搜索只是一个问题
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