我将如何过滤对象数组：如果 id 编号是连续的

Question

I have a JSON file that has an array of objects with data inside:

[
    {
    "_id": "62bd5fba34a8f1c90303055c",
    "index": 0,
    "email": "mcdonaldholden@xerex.com",
    "nameList": [
      {
        "id": 0,
        "name": "Wendi Mooney"
      },
      {
        "id": 2,
        "name": "Holloway Whitehead"
      }
    ]
    },
    {
    "_id": "62bd5fbac3e5a4fca5e85e81",
    "index": 1,
    "nameList": [
      {
        "id": 0,
        "name": "Janine Barrett"
      },
      {
        "id": 1,
        "name": "Odonnell Savage"
      },
      {
        "id": 2,
        "name": "Patty Owen"
      }
    ]
    }, ...

My job is to filter the arrays that have more than two names and if their id are consecutive. I managed to sort users with more than two user.name but cant grasp the concept of filtering consecutive id numbers

let lister3 = userData.filter(names => names?.nameList?.filter(name => name?.name).length > 2)

Which returns me the objects with more than two user names.

Answer 1

filter takes a function that returns true if you want to retain the item or false if not. In this function, you could check the length of the nameList , and then iterate over its members and make sure their id s are consecutive:

retult = userData.filter(u => {
    if (u.nameList.length < 2) {
        return false;
    }
    for (let i = 1; i < u.nameList.length; ++i) {
        if (u.nameList[i].id != u.nameList[i - 1].id + 1) {
            return false;
        }
    }
    return true;
});

Answer 2

a item should need tow conditions,one is nameList length is two,the other is the itemId of nameList is consecutive; so first as you do:

`
let lister3 = userData.filter(names => names?.nameList?.filter(name => name?.name).length > 2)
`

; then `

let lister4 =  lister3.filter(names=>{
let idOfStr = names.nameList?.sort((a,b)=>a.id-b.id).map(item=>item.id).join("");
let resultStr = Array.from(idOfStr.length).fill(+idOfStr[0]).map((item,index)=>+item+index).join('');
return idOfStr === resultStr
})

`

hope this is useful for you