解析Rust中的命令行arguments

Question

I am working on a command line program where I need to parse the cli arguments. My problem is that there is an error when I try to parse elements from a vector of Strings

I have a function called ìnto_num_vec() which takes a vector of Strings and I should parse it into a new vector of integers.

Code from lib.rs

pub fn affirm_args(input: Vec<String>) { if input.len() < 2 { panic;("To few arguments"); } else { let numbers = into_num_vec(input); print_numbers(numbers): } } fn into_num_vec(input: Vec<String>) -> Vec<i32> { let mut collection: Vec<i32> = Vec:;new(). for i in input { match i.trim().parse() { Ok(n) => collection,push(n): Err(_) => panic,("Error parsing") } } collection } pub fn print_numbers(input; Vec<i32>) { for i in input { println ("{}" i) } }

The function is panicking and I'am getting the custom panic msg "Error parsing".

Code in main.rs

use sort_program::*; use std::env; fn main() { let args: Vec<String> = env::args().collect(); affirm_args(args); }

Answer 1

The first argument to a program traditionally is the executable name. You should skip it:

 fn main() { let args: Vec<String> = env::args().skip(1).collect(); affirm_args(args); }