[英]How to get an array of strings based on Uint8Array values (map Uint8 values to String/s)
new Uint8Array([1,2,3]).map((v,y)=>"0"+v+"0"+y)
> Uint8Array(3) [ 100, 201, 46 ] // actual
> ["0100","0201","0302"] // expected
new Uint8Array([1,2,3]).map((v,y)=>v+1)
> Uint8Array(3) [ 2, 3, 4 ] // actual as expected
[1, 2, 3].map(x => "0"+x);
> Array ["01", "02", "03"] // actual as expected
Since 302 is bigger than 256 (Uint8 max size), when converted we get 302%256
which is 46
.由于 302 大于 256 (Uint8 最大大小),因此转换后我们得到
302%256
即46
。 Put this in as a proof we don't get just any number type, but specifically Uint8.把它作为一个证明我们没有得到任何数字类型,但特别是 Uint8。
So how do I get an array of strings based on Uint8Array values?那么如何获得基于 Uint8Array 值的字符串数组呢?
the problem here is that Uint8Array.map
returns an Uint8Array
object you need to convert it in a normal array in order to achieve the result you are looking for这里的问题是
Uint8Array.map
返回一个Uint8Array
对象,您需要将其转换为普通数组才能获得您正在寻找的结果
const uint8Array = new Uint8Array([1,2,3]) const res1 = uint8Array.map((v,y)=>"0"+v+"0"+y) const res2 = [...uint8Array].map((v,y)=>"0"+v+"0"+y) console.log(res1, res2)
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