Python Hex-String - 每 x 个字符添加一个空格

Question

I have a string in python, that looks like this: str = '02001400ce01', which is in hex: 0x02, 0x00, 0x14, 0x00,0xce, 0x01. I would like now to make the string to:

str = '02 00 14 00 ce 01'

How can I do this?

Answer 1

This code will work.

str = '02001400ce01'
offset = 0
for i in range(len(str)):
    if i % 2 == 1:
        offset += 1 
        #insert a space at position i
        str = str[:i+offset] + ' ' + str[i+offset:]
print(str)

Answer 2

You can do like this:

string = '02001400ce01'
str_space = ' '.join(s1 + s2 for s1, s2 in zip(string[::2], string[1::2]))

Output:

'02 00 14 00 ce 01'

Answer 3

您可以简单地使用map和range来生成字符串。

" ".join(list(map(lambda y: x[y:y+2],range(0,len(x),2))))