单个关键字中的多个单词并在python中的数据中计算它们

Question

I'm trying to run the following code in python in order to count the keywords in the specific values of my dictionary. Suppose my keywords = ['is', 'my'] and it works fine for me but when my keywords are keywords = ['is', 'my name'] then it doesn't count the keyword my name . I don't know what mistake I'm doing. if anyone can see the code and help me out. thank you

from collections import Counter
import json 
from typing import List, Dict


keywords = ['is', 'my name']

def get_keyword_counts(text: str, keywords: List[str]) -> Dict[str, int]:
    return {
        word: count for word, count in Counter(text.split()).items()
        if word in set(keywords)
    }

    data = {
        "policy": {
            "1": {
                "ID": "ML_0",
                "URL": "www.a.com",
                "Text": "my name is Martin and here is my code"
            },
            "2": {
                "ID": "ML_1",
                "URL": "www.b.com",
                "Text": "my name is Mikal and here is my code"
            }
        }
    }
    
    for policy in data['policy'].values():
        policy.update(get_keyword_counts(policy['Text'], keywords))
    print(json.dumps(data, indent=4))

Answer 1

The substring "my name" is also splitted in get_keyword_counts so there is no actual value "my name", they are apart: "my" and "name". I guess you want to count it as a whole, so there is what you need:

def get_keyword_counts(text: str, keywords: List[str]) -> Dict[str, int]:
    return {
        word: text.count(word) for word in keywords
    }

Answer 2

您正在使用text.split() ，它最终将"my"和"name"分开，所以改为使用count()并且应该这样做。