如何从从 file1 查询到 file2 的匹配结果中编写具有不同列的 file3？

Question

I have file1.txt and file2.txt with the following structure

File1.txt

5511913332222

5511910000023

5511910000029

5511910000034

File2.txt

5511910000029|BLOCKED|7|30/07/2021 02:19:43

5511910000034|AVAIL|7|30/07/2021 03:11:53

5511910000048|AVAIL|7|30/07/2021 04:10:25

5511910000073|BLOCKED|7|30/07/2021 07:20:33

I want to write a file3.txt with the 1st and 2nd columns of the file2 where the 1st column matched the 1st column of file1.txt.

File3.txt

5511910000029|BLOCKED

5511910000034|AVAIL

I have tried some tricks with awk but I couldn't get the expected result. Could anyone please help me?

awk 'NR==FNR{a[$0]}NR>FNR && $0 in a{print}' file1 file2 > file3

Answer 1

$ awk -F'|' -v OFS='|' 'NR==FNR {a[$1];next} ($1 && $1 in a){print $1,$2}' File1.txt File2.txt 
5511910000034|AVAIL

To save output to File3.txt ... {print $1,$2 > "File3.txt"} ...

Answer 2

$ join -o 2.1,2.2 -t '|' -j 1 <(sort -k1 -t '|' file1.txt) <(sort -k1 -t '|' file2.txt)
5511910000029|BLOCKED
5511910000034|AVAIL

This means join on the first field in both files ( -j 1 ), outputting ( -o ) the first and second fields ( .1 , .2 ) of the second file ( 2. ), using bar as a field delimiter ( -t '|' ), and sorting the inputs ( <(sort) ) on the first field ( -k1 ) with bar as a delimiter (`-t '|' again).

This assumes that file1.txt and file2.txt 1) aren't already sorted; 2) can be sorted; 3) don't have every other line blank, like you show in the question.

Answer 3

As the lines in file1 consist of only digits, you can verify that using $0 ~ /^[[:digit:]]+$/ before setting them as a key in a

Set the output field separator to | and set the field separator of file2 also to |

awk -v OFS="|" '
NR==FNR && $0 ~ /^[[:digit:]]+$/ {
  a[$0]
  next
}
($1 in a){
  print $1,$2
}
' file1  FS="|" file2 > file3

The content of file3 :

5511910000029|BLOCKED
5511910000034|AVAIL