如何返回列表列表中不在 Python 中其他列表中的所有项目？

Question

I have 2 list of lists:

list1: [[1,2,3],[2,5],[6,7,4]]
list2: [[1,3],[2],[6,4],[9,0,3]]

I want to do few things:

1. Find every number that is in list 1 but is not in list 2, store it in a new list, and then append this new list to list2. In our case: new_list = [5,7] and then, we will add it to list2 = [[1,3],[2],[6,4],[9,0,3],[5,7]]

2. Then, I want to remove duplicates of numbers from each list1 and list 2:
   In our case: list1 = [[1,3],[2,5],[6,7,4]], list2 = [[1],[2],[6,4],[9,0,3],[5,7]]

I have an implementation using For loops, but I need something more elegant for that. Can you help me please find out a way?

Answer 1

使用 Python，您可以使用集合推导来完成第一部分：

list2.append(list({i for j in list1 for i in j}.difference({i for j in list2 for i in j})))