[英]How to remove new Function with Anonymous function in javascript
I am trying to replace eval/new Function with corresponding anonymous function.我正在尝试用相应的匿名函数替换 eval/new Function。
Existing Code -现有代码 -
var y = 2
var fn = new Function("return" +y)
console.log(fn)
When i print fn output is当我打印fn输出是
ƒ anonymous(
) {
return2
}
Refactored code which i am writing -我正在编写的重构代码 -
var y = 2
var fn1 = function() {return y}
console.log(fn1)
But fn1 in this case is但在这种情况下 fn1 是
ƒ () {return y}
Any pointers how can i get the same output as fn ƒ anonymous() {return2}
using my own anonymous function.任何指针我如何使用我自己的匿名函数获得与 fn
ƒ anonymous() {return2}
相同的输出。
You can't (at least not without using another version of eval
).你不能(至少在不使用另一个版本的
eval
的情况下不能)。
You can get the same effect (ie not having a mutable y
) by using a closure.通过使用闭包,您可以获得相同的效果(即没有可变的
y
)。
var y = 2 var fn1 = function(closure_y) { return function() { return closure_y; } }(y) y = 3; console.log(fn1())
If your code depends on a function stringifying itself in a particular way, then you should probably rewrite the code so it no longer depends on that.如果您的代码依赖于以特定方式对自身进行字符串化的函数,那么您可能应该重写代码,使其不再依赖于它。
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