为什么即使我没有使用任何“str”命名变量，我也会收到（“str”函数不可调用）错误？

Question

originalMSG = ['1','2','3','4','5','6','7','8','9','0','a','b','c','d','e','f','g','h','i','j','k','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z',' ']
codedMSG = ['v', 'u', '0', 's', '1', 'r', 'o', 'x', 'a', 'p', 'y', 'd', 'k', 'b', 'z', 'g', 'q', 'l', '5', ' ', 'w', 'c', 'm', '8', 'h', '4', 't', '3', '6', 'k', 'n', '7', 'j', '2', '9', 'e', 'i', 'f']
str2 = 'wello'
h=[]
#print(str2.index('w'))
for i in range(0, len(str2)):
    h=codedMSG(originalMSG.index(str2(i)))
print(str2)

It is giving me error in 8th line TypeError: 'str' object is not callable. in line 7

Answer 1

Replace str2(i) with str2[i] - indexing rather than calling

Also, do the same with codedMSG(...) - replace with codedMSG[...]

I think this is what you want to do:

originalMSG = ['1','2','3','4','5','6','7','8','9','0','a','b','c','d','e','f','g','h','i','j','k','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z',' ']

codedMSG = ['v', 'u', '0', 's', '1', 'r', 'o', 'x', 'a', 'p', 'y', 'd', 'k', 'b', 'z', 'g', 'q', 'l', '5', ' ', 'w', 'c', 'm', '8', 'h', '4', 't', '3', '6', 'k', 'n', '7', 'j', '2', '9', 'e', 'i', 'f']

str2 = 'wello'
h=[]

for i in range(0, len(str2)):
    h.append(codedMSG[originalMSG.index(str2[i])])
    
print(''.join(h))

Output: 2zmm4