[英]Reverse binary reading
I have a document that shows a data in HEX, and split it into multi part (head, TransactionID, MessageType and ...) There is a problem in this document, and it is for example for TID they write something like this:我有一个以 HEX 显示数据的文档,并将其拆分为多个部分(head、TransactionID、MessageType 和 ...)此文档中存在问题,例如,对于 TID,他们编写了如下内容:
TID: 0xe0380000 = 14560
As i know converting 0xe0380000
to decimal will be 3761766400
, not 14560
.据我所知,将
0xe0380000
转换为十进制将是3761766400
,而不是14560
。 I figured out that the way they read data is something like this:我发现他们读取数据的方式是这样的:
For a given number such as 0xe0380000
they rotate the number and it will be 0x0000038e0
now the 0x0000038e0
in decimal is 14560
.对于给定的数字,例如
0xe0380000
他们旋转数字,现在它将是0x0000038e0
现在十进制的0x0000038e0
是14560
。 What is the reason for such a method to convert?这种方法转换的原因是什么? Is it any thing to do with
Uint32
part in the documentation table?与文档表中的
Uint32
部分有关吗?
In the documentation table from the link that you've provided, the type for TID
is Uint32-LittleEndian
and the size is 4 bytes
.在您提供的链接的文档表中,
TID
的类型是Uint32-LittleEndian
,大小是4 bytes
。 Endianness indicates the order of bytes: Endianness表示字节的顺序:
Little Endian (LE) : - 14560 (10)
- > e0 38 00 00
小尾数 (LE) : -
14560 (10)
-> e0 38 00 00
Big Endian (BE) : 14560 (10)
-> 00 00 38 e0
大端 (BE) :
14560 (10)
-> 00 00 38 e0
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