如何在 Python 中进行条件计算

Question

I have a sample data that looks like this.

Column DateDuration was calculated in Excel, following below logic:

• DateDuration between SecondDate and FirstDate >= 28, then DateDuration = SecondDate - FirstDate.
• DateDuration between SecondDate and FirstDate <28, if ThirdDate = nan, then DateDuration = SecondDate - FirstDate.
• DateDuration between SecondDate and FirstDate <28, if ThirdDate = not nan, then consider (ThirdDate - FirstDate):
  • ThirdDate - FirstDate >= 28, then DateDuration = ThirdDate - FirstDate.
  • ThirdDate - FirstDate < 28, if FourthDate = nan, then DateDuration = ThirdDate - FirstDate.
  • ThirdDate - FirstDate < 28, if FourthDate = not nan, then DateDuration = FourthDate - FirstDate.

I would like to calculate DateDuration in Python but do not know how to do about this.

Types of data in Python:

• ID int64
• FirstDate object
• SecondDate object
• ThirdDate object
• FourthDate object

I am new to Python. Any help would be greatly appreciated!!

import pandas as pd
import numpy as np
df['FirstDate'] = pd.to_datetime(df['FirstDate'])
df['SecondDate'] = pd.to_datetime(df['SecondDate'])
df['DayDifference2'] = (df['SecondDate']) -(df['FirstDate'])
df['DayDifference3'] = (df['ThirdDate']) -(df['FirstDate'])
df['DayDifference4'] = (df['FourthDate']) -(df['FirstDate'])
    
x = df['DayDifference2'].dt.days
y = df['DayDifference3'].dt.days
z = df['DayDifference4'].dt.days

condlist = [x<28, x>=28]
choicelist = [(df['ThirdDate']) -(df['FirstDate']), (df['SecondDate']) -(df['FirstDate'])]
np.select(condlist, choicelist)

My data:

ID	FirstDate	SecondDate	ThirdDate	FourthDate	DateDuration
2914300	2021-09-23	2021-10-07	2021-11-29	2021-12-20	67
3893461	2021-09-08	2021-10-06	2022-04-07		211
4343075	2021-06-23	2021-09-27			96
4347772	2021-06-23	2021-09-27			96
4551963	2021-08-02	2021-10-14	2022-03-11		73
4893324	2021-09-30	2021-10-01	2022-03-03	2022-03-10	154
5239991	2021-06-24	2021-08-26	2021-09-25	2022-02-03	63
8454947	2021-09-28	2021-10-05			7
8581390	2021-09-27	2022-03-21	2022-03-25		175
8763766	2021-09-20	2021-10-04	2021-12-09		80
9144185	2021-06-18	2021-06-23			5
9967685	2021-09-13	2021-10-29	2022-02-07	2022-03-23	46
11367560	2021-08-31	2021-09-28	2021-10-21	2022-02-11	51

Answer 1

Refer to the time module built-in. It allows for more time class types that I actually used for my own workout routine maker.

import datetime as dt

# particularly the types:
dt.timedelta(1)
# and
dt.time(minute=0, second=0)
# there are also date classes you can use. 

Documentation: https://docs.python.org/3/library/datetime.html

Answer 2

import pandas as pd
import numpy as np

df = pd.read_csv('date_example.csv')
df.loc[:,'FirstDate':'FourthDate'] = df.loc[:,'FirstDate':'FourthDate'].astype('datetime64[ns]')
df

NaT is a missing value of datetime64[ns] type

Conditions & Choices

conditions = [
    (df['SecondDate'] - df['FirstDate']).dt.days >= 28,
    ((df['SecondDate'] - df['FirstDate']).dt.days < 28) & df['ThirdDate'].isna(),
    ((df['SecondDate'] - df['FirstDate']).dt.days < 28) & df['ThirdDate'].notna() & ((df['ThirdDate'] - df['FirstDate']).dt.days >= 28),
    ((df['SecondDate'] - df['FirstDate']).dt.days < 28) & df['ThirdDate'].notna() & ((df['ThirdDate'] - df['FirstDate']).dt.days < 28) & df['FourthDate'].isna(),
    ((df['SecondDate'] - df['FirstDate']).dt.days < 28) & df['ThirdDate'].notna() & ((df['ThirdDate'] - df['FirstDate']).dt.days < 28) & df['FourthDate'].notna()
]

choices = [
    (df['SecondDate'] - df['FirstDate']).dt.days,
    (df['SecondDate'] - df['FirstDate']).dt.days,
    (df['ThirdDate'] - df['FirstDate']).dt.days,
    (df['ThirdDate'] - df['FirstDate']).dt.days,
    (df['FourthDate'] - df['FirstDate']).dt.days
]

df['Duration'] = np.select(conditions, choices)
df

Result

Discussion: There are some differences, eg, second row, ID = 3893461 , according to your conditions(DateDuration between SecondDate and FirstDate >= 28, then DateDuration = SecondDate - FirstDate.), SecondDate - FirstDate of ID = 3893461 is 28 , same thing happened on last row, ID = 11367560