C语言的奇数模式

Question

Can anyone tell me how to print the following pattern in C:

1
13
135
1357
13579

(From OP comment:)

I tried this but it prints each value two times a row:

#include <stdio.h> 
#include <stdlib.h> 
int main(void) { 
    int i,j,limit; 
    printf("limit"); 
    fflush( stdout ); 
    scanf("%d",&limit); 
    for(i=1;i<=limit;i++){
        for(j=1;j<=i;j++){
            if(j%2==1){ 
                printf("%d",j); 
            }
        }
        printf("\n"); 
    } 
    return EXIT_SUCCESS; 
}

Answer 1

Your code prints each number twice, once for that value (the odd value) and again on the following value (the even value).

Better would be to loop over just the odd numbers and avoid that worry (and also avoid the additional test for odd):

#include <stdio.h> 
#include <stdlib.h> 
int main(void) { 
    int i,j,limit; 
    printf("limit"); 
    fflush( stdout ); 
    scanf("%d",&limit); 
    for(i=1;i<=limit;i+=2){
        for(j=1;j<=i;j+=2){
            printf("%d",j); 
        }
        printf("\n"); 
    } 
    return EXIT_SUCCESS; 
}

Answer 2

printf("1 13 135 1357 13579");