replace/replaceAll 不是函数

Question

I'm trying to use replace in order to remove some characters in a 2d array of strings, but I keep incountering an issue:

      dataArr[j,k] = dataArr[j,k].replaceAll(mCH, "");
                              ^

TypeError: dataArr[(j , k)].replaceAll is not a function
at Object.<anonymous> (C:\Users\magshimim\say-hi-to-sheli-from-me\rafaels-crypto-ninja\thingy\server\index.js:45:35)
at Module._compile (node:internal/modules/cjs/loader:1105:14)
at Object.Module._extensions..js (node:internal/modules/cjs/loader:1159:10)
at Module.load (node:internal/modules/cjs/loader:981:32)
at Function.Module._load (node:internal/modules/cjs/loader:822:12)
at Function.executeUserEntryPoint [as runMain] (node:internal/modules/run_main:77:12)
at node:internal/main/run_main_module:17:47

this is the part of my code using the function:

for (let j = 0; j < dataArr.length; j++)
{
  for (let k = 0; k < dataArr[j].length; k++)

  {
      dataArr[j][k] = dataArr[j][k].replaceAll('"', "");
      dataArr[j][k] = dataArr[j][k].replaceAll(":", "");
      dataArr[j][k] = dataArr[j][k].replaceAll("I", "");
      dataArr[j][k] = dataArr[j][k].replaceAll("L", "");
      dataArr[j][k] = dataArr[j][k].replaceAll("S", "");
      dataArr[j][k] = dataArr[j][k].replaceAll("}", "");
  }
}

Do I need to download anything? maybe there's a problem with my code?

Answer 1

That's not how you index a 2-dimensional array (well, array of arrays; there are no 2-dimensional arrays in JavaScript).

You're looking for dataArr[j][k] , not dataArr[j,k] .

[j, k] evaluates to just k since the comma is parsed as the comma sequence operator ; j is evaluated and thrown away, and k is the result. It is then used to index the top-level dataArr , and indeed, replaceAll is not a method on the arrays nested within.

You could also rewrite this as a double map and use a regexp so you don't need to spell out all of those replacements:

dataArr = dataArr.map(row => row.map(c => String(c).replace(/[":ILS}]+/g, "")));

Answer 2

You can use the .replace function instead of replaceAll , if the later is not available.

"any string".replace(new RegExp("to replace", "g"), "new text")

This is by using new RegExp("text to replace", "g") as a string to search