使用外部 URL 时的 Pandas read_csv 响应代码

Question

I'm replacing requests.get() with pd.read_csv() and would like to write some exception logic if pandas does not get the equivalent of a status code 200.

With requests, I can write:

response = requests.get(report_url)
if response.status_code != 200:

How can I apply the same logic to pd.read_csv() ? Are there any status codes I can check on?

Answer 1

My suggestion is to write a custom reader that makes it possible to check that a URL is valid before reading it although this defeats the purpose

import requests
def custom_read(url):
    try: 
        return_file = pd.read_csv(url) 
    except requests.exceptions.HTTPError as err:
        raise
    else:
        return return_file

A valid URL will work

my_file = custom_read("https://people.sc.fsu.edu/~jburkardt/data/csv/addresses.csv")

This fails and raises a requests error

my_file1 = custom_read("https://uhoh.com")

Otherwise, there is no way to access the status code of a URL for a DataFrame object once it has been read.

Answer 2

You can use url in read_csv() but it has no method to gives you status code. It simply raises error when it has non-200 status code and you have to use try/except to catch it. You have example in other answer.

But if you have to use requests then you can later use io.StringIO to create file-like object (file in memory) and use it in read_csv() .

import io
import requests
import pandas as pd

response = requests.get("https://people.sc.fsu.edu/~jburkardt/data/csv/addresses.csv")

print('status_code:', response.status_code)

#if response.status_code == 200:
if response.ok:
    df = pd.read_csv( io.StringIO(response.text) )
else:
    df = None

print(df)

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The same way you can use io.StringIO when you create web page which gets csv using HTML with <form> .

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As I know read_csv(url) works in similar way - it uses requests.get() to get file data from server and later it uses io.StringIO to read data.