检查传递给 bash 脚本的参数是否与文件名相同

Question

I want to check if the argument passed while executing the script matches the prefix of a filename in my directory. I m facing binary operator expected error with my code. Does any body have any alternative approach ?

./test.sh abc

fucn_1(){
if [ -e $file_name* ] ; then 
 func_2
else 
 echo "file not found" 
 exit
fi
}

if [ $1 == abc ];
then 
file_name=`echo $1`
fucn_1
elif  [ $1 == xyz ];
then 
file_name=`echo $1`
fucn_1

while running I m passing abc as the argument such that then script can then check if the filenames starting with 'abc' is present or not in the directory. the dir has files :-

abc_1234.txt
abc_2345.txt

Answer 1

The glob $file_name* expands to a list of files. You ran [ -e abc_1234.txt abc_2345.txt ] which gives an error, since [ -e expects only one file, not two.

Try something like ...

#! /usr/bin/env bash
shopt -s nullglob
has_args() { (( "$#" > 0 )); }
if has_args "$1"*; then
  echo "$1 is a prefix of some file or dir"
else
  echo "$1 is not a prefix of any file or dir"
fi