如何将自定义的 zsh 函数参数传递给块内 zmv 命令？

Question

I am creating a zsh script that batch resize, convert and rename set of images for web dev.

The zsh function is structured like below:

function img() {
    # lines of "magick -resize" and "magick mogrify -format"

    autoload zmv
    zmv '(*).(*)' '$1.$2'
}

How can i pass an argument from the command like img "something" so the zmv in-function command can be:

zmv '(*).(*)' 'something$1.$2'

Thanks!

Answer 1

This will prefix the second argument to zmv with the first argument passed to img :

img() {
  zmv '(*).(*)' $1'$1.$2'
}

This works because the first $1 is unquoted and thus evaluated before it is passed to zmv , whereas '$1.$2' is in single quotes and thus passed as a literal string.