[英]in a XML, how to remove one complete node if the text of the grandchilds are not the same, with XSLT1.0
I have this XML from which I want to remove all nodes that do not comply with having equal texts in their grandchilds elements, detailed information after the input XML.我有这个 XML,我想从中删除所有不符合其孙元素中具有相同文本的节点,输入 XML 之后的详细信息。
The input XML:输入 XML:
<COMPANY>
<SCHEDULES>
<OFFICE name="BCO">
<DEPARTAMENT name="BCO1">
<days>monday:friday</days>
<code>Y</code>
<indice>0</indice>
</DEPARTAMENT>
<TEAM name="BCO2">
<days>monday:friday</days>
<code>I</code>
<indice>0</indice>
</TEAM>
</OFFICE>
<OFFICE name="RCO">
<DEPARTAMENT name="RCO1">
<days>monday:tuesday</days>
<code>Y</code>
<indice>0</indice>
</DEPARTAMENT>
<TEAM name="RCO2">
<days>monday:wednesday</days>
<code>t</code>
<indice>0</indice>
</TEAM>
</OFFICE>
<OFFICE name="LCO">
<DEPARTAMENT name="LCO1">
<days>wednesday:saturday</days>
<code>Y</code>
<indice>0</indice>
</DEPARTAMENT>
<TEAM name="LCO2">
<days>wednesday:saturday</days>
<code>In</code>
<indice>0</indice>
</TEAM>
</OFFICE>
<OFFICE name="ACO">
<DEPARTAMENT name="ACO1">
<days>monday</days>
<code>a</code>
<indice>1</indice>
</DEPARTAMENT>
<TEAM name="ACO2">
<days>tuesday</days>
<code>a</code>
<indice>1</indice>
</TEAM>
</OFFICE>
</SCHEDULES>
</COMPANY>
I want to delete all the element OFFICE, if the text of the days tag inside DEPARTAMENT and TEAM, are not the same, that way I would have an output like this :我想删除所有元素OFFICE,如果DEPARTAMENT和TEAM中的days标签的文本不一样,那么我会有这样的输出:
<COMPANY>
<SCHEDULES>
<OFFICE name="BCO">
<DEPARTAMENT name="BCO1">
<days>monday:friday</days>
<code>Y</code>
<indice>0</indice>
</DEPARTAMENT>
<TEAM name="BCO2">
<days>monday:friday</days>
<code>I</code>
<indice>0</indice>
</TEAM>
</OFFICE>
<OFFICE name="LCO">
<DEPARTAMENT name="LCO1">
<days>wednesday:saturday</days>
<code>Y</code>
<indice>0</indice>
</DEPARTAMENT>
<TEAM name="LCO2">
<days>wednesday:saturday</days>
<code>In</code>
<indice>0</indice>
</TEAM>
</OFFICE>
</SCHEDULES>
</COMPANY>
Im trying to use this XSLT but I have an error for the XPath expression.我尝试使用此 XSLT,但 XPath 表达式出现错误。
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:str="http://exslt.org/strings"
extension-element-prefixes="str">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//SCHEDULES/OFFICE/DEPARTAMENT/days[text()]=//SCHEDULES/OFFICE/TEAM/days[text()]"/>
</xsl:stylesheet>
How can I do this using XSLT 1.0, thank you for any answers that may help我如何使用 XSLT 1.0 做到这一点,感谢您提供任何可能有帮助的答案
I think you want to do:我想你想做:
XSLT 1.0 XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="OFFICE[DEPARTAMENT/days != TEAM/days]"/>
</xsl:stylesheet>
Applied to your example input, this will return:应用于您的示例输入,这将返回:
Result结果
<?xml version="1.0" encoding="UTF-8"?>
<COMPANY>
<SCHEDULES>
<OFFICE name="BCO">
<DEPARTAMENT name="BCO1">
<days>monday:friday</days>
<code>Y</code>
<indice>0</indice>
</DEPARTAMENT>
<TEAM name="BCO2">
<days>monday:friday</days>
<code>I</code>
<indice>0</indice>
</TEAM>
</OFFICE>
</SCHEDULES>
</COMPANY>
This is different from the result you show - but the result you show makes no sense, because <OFFICE name="LCO">
has different data than the source.这与您显示的结果不同 - 但您显示的结果没有意义,因为<OFFICE name="LCO">
具有与源不同的数据。
To understand how this works, you should learn about predicates .要了解这是如何工作的,您应该了解谓词。
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