[英]How to remove double quotes without escape (^) in cmd/ batchfile?
Note: as the OP is a new user, I'm editing the question with reproducible details so that it doesn't get closed.注意:由于 OP 是新用户,我正在使用可重现的详细信息编辑问题,以免它被关闭。 It's a good question, but was originally confusing.
这是一个很好的问题,但最初令人困惑。
The Windows username is: jhon^smith Windows 用户名是:jhon^smith
ECHO %username%
output : jhonsmith
My expectation:我的期望:
jhon^smith
If I use:如果我使用:
echo "%username%"
then the output is:那么输出是:
"jhon^smith"
How can I remove the double quotes but keep the caret, which is actually part of the username?如何删除双引号但保留插入符号,这实际上是用户名的一部分?
This should work:这应该有效:
for /f %a in ("%username%") do echo %a
output:输出:
jhon^smith
(btw: It should be spelt john^smith
but never mind.) (顺便说一句:应该拼写为
john^smith
但没关系。)
Explanation:解释:
In the command echo %username%
, cmd.exe
replaces %username%
with its actual content, so the command becomes echo jhon^smith
.在命令
echo %username%
中, cmd.exe
将%username%
替换为其实际内容,因此命令变为echo jhon^smith
。 This is then parsed, the the ^
is processed as the escape character, so it replaces ^s
with s
.然后对其进行解析,将
^
处理为转义字符,因此它将^s
替换为s
。
In the command for /f %a in ("%username%") do echo %a
, the quoted string is treated as a string without the quotes, and no parsing of ^
is performed.在
for /f %a in ("%username%") do echo %a
命令中,带引号的字符串被视为不带引号的字符串,并且不执行^
解析。 Type for /?
for /?
for more details.更多细节。
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