[英]How to define output parameter in Task<IActionResult>
I'm switching tech stacks so I'm a bit confused here.我正在切换技术堆栈,所以我在这里有点困惑。 This function should return an object此 function 应返回 object
public async Task<IActionResult> Search(CoinModel Coin)
{
var date = Coin.tracking_date.ToLocalTime().ToString("dd/MM/yyyy");
var dateformat = DateTime.Parse(System.Web.HttpUtility.UrlDecode(date + " 00:00:00.0000000"));
var issue = await _db.Coins.SingleOrDefaultAsync(c => c.coin == Coin.coin.ToUpper() && c.tracking_date == dateformat);
return issue == null ? NotFound() : Ok(issue);
}
But I can't seem to access the result like this但我似乎无法访问这样的结果
var search = await Search(Coin);
return search.id;
You return an IActionResult in this method but your return type is a Coin (Entity).您在此方法中返回 IActionResult,但您的返回类型是 Coin(实体)。 You should change the return type of your method.您应该更改方法的返回类型。 I assume that class name of coin entity is 'Coin'我假设硬币实体的 class 名称是“硬币”
[NonAction]
public async Task<Coin> Search(CoinModel Coin)
{
var date = Coin.tracking_date.ToLocalTime().ToString("dd/MM/yyyy");
var dateformat = DateTime.Parse(System.Web.HttpUtility.UrlDecode(date + " 00:00:00.0000000"));
var issue = await _db.Coins.SingleOrDefaultAsync(c => c.coin == Coin.coin.ToUpper() && c.tracking_date == dateformat);
return issue == null ? NotFound() : Ok(issue);
}
By the way, as this method is not an Action method, you can define it using [NonAction]顺便说一句,由于该方法不是 Action 方法,您可以使用 [NonAction] 来定义它
I would suggest a helper method.我会建议一个辅助方法。
private async Task<Coin> SearchAsync(CoinModel Coin)
{
var date = Coin.tracking_date.ToLocalTime().ToString("dd/MM/yyyy");
var dateformat = DateTime.Parse(System.Web.HttpUtility.UrlDecode(date + " 00:00:00.0000000"));
var issue = await _db.Coins.SingleOrDefaultAsync(c => c.coin == Coin.coin.ToUpper() && c.tracking_date == dateformat);
return issue == null ? NotFound() : Ok(issue);
}
public async Task<IActionResult> Search(CoinModel coin)
{
var issue = await SearchAsync(coin);
return issue == null ? NotFound() : Ok(issue);
}
Btw.顺便提一句。 In C# the convetion is to start argument with a common letter, so CoinModel coin
, not CoinModel Coin
.在 C# 中,约定是用一个普通字母开始参数,所以CoinModel coin
,而不是CoinModel Coin
。
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