[英]Double iteration through chars in a string and nodes in XSLT - how to do it with recursion?
I need to replace some characters in a string stored in <p>
with <app>
nodes which contain a matching char (or substring) in a child element <lem>
.我需要用
<app>
节点替换存储在<p>
中的字符串中的一些字符,这些节点在子元素<lem>
中包含匹配的字符(或子字符串)。 Each <app>
contains only one <lem>
at the top, and an arbitrary number of other nodes below it.每个
<app>
在顶部只包含一个<lem>
,在它下面有任意数量的其他节点。 Each <app>
only refers to a single character in the text, and they are placed in order.每个
<app>
只引用文本中的单个字符,并且它们是按顺序排列的。
I am new to XSLT, and cannot come up with a good recursion to do this -- I'm kind of stuck in the java or MATLAB mindset of iterating over i = 1:n
and j= 1:m
, and I understand that this is no good for taking advantage of recursion in XSLT... Thanks for your help!!!我是 XSLT 的新手,无法想出一个好的递归来做到这一点——我有点陷入 java 或 MATLAB 迭代
i = 1:n
和j= 1:m
的心态,我明白这不利于利用 XSLT 中的递归...感谢您的帮助!!!
<div>
<p>SOMEWONDERFULOLDTEXT</p>
<app>
<lem>O</lem>
<rdg>Ø</rdg>
</app>
<app>
<lem>W</lem>
<rdg>V</rdg>
</app>
<app>
<lem>O</lem>
<rdg>Ö</rdg>
</app>
<app>
<lem>E</lem>
<rdg>Ë</rdg>
<rdg>ę</rdg>
</app>
</div>
My stylesheet so far is this, but I know it doesn't work because it is iterating through the text for every <app>
, which is wrong.到目前为止,我的样式表是这样的,但我知道它不起作用,因为它遍历每个
<app>
的文本,这是错误的。
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:tei="http://www.tei-c.org/ns/1.0" xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs tei" version="3.0">
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*"/>
</xsl:copy>
</xsl:template>
<!-- now build the apparatus -->
<xsl:template match="tei:div">
<xsl:param name="thisBlock" select="./tei:p/node()"/>
<xsl:for-each select="tei:app">
<xsl:variable name="thisApp" select="."/>
<xsl:for-each
select="tokenize(replace(replace($thisBlock, '(.)', '$1\\n'), '\\n$', ''), '\\n')">
<xsl:choose>
<xsl:when test="$thisApp/tei:lem/text() = .">
<xsl:copy-of select="$thisApp"></xsl:copy-of>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates></xsl:apply-templates>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
The result I want is the following, although I am getting a frightful mess with each <app>
containing the variant readings of O printed for every single O in the text, regardless of order (of course, because I don't know how to iterate linearly along two "arrays")...我想要的结果如下,尽管我对每个
<app>
都感到非常混乱,其中包含为文本中的每个 O 打印的 O 的变体读数,无论顺序如何(当然,因为我不知道如何沿两个“数组”线性迭代)...
<div>
<p>S<app>
<lem>O</lem>
<rdg>Ø</rdg>
</app>ME<app>
<lem>W</lem>
<rdg>V</rdg>
</app><app>
<lem>O</lem>
<rdg>Ö</rdg>
</app>ND<app>
<lem>E</lem>
<rdg>Ë</rdg>
<rdg>ę</rdg>
</app>RFULOLDTEXT</p>
</div>
I suppose this is one way you could look at it:我想这是你可以看待它的一种方式:
XSLT 1.0 XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="div">
<div>
<p>
<xsl:call-template name="process">
<xsl:with-param name="string" select="p"/>
<xsl:with-param name="app" select="app"/>
</xsl:call-template>
</p>
</div>
</xsl:template>
<xsl:template name="process">
<xsl:param name="string"/>
<xsl:param name="app"/>
<xsl:choose>
<xsl:when test="$app">
<xsl:variable name="char" select="$app[1]/lem" />
<xsl:value-of select="substring-before($string, $char)" />
<xsl:copy-of select="$app[1]"/>
<!-- recursive call -->
<xsl:call-template name="process">
<xsl:with-param name="string" select="substring-after($string, $char)"/>
<xsl:with-param name="app" select="$app[position()>1]"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
This could probably be smartened up a bit in XSLT 3.0, but I prefer the clarity of the named template method.这可能会在 XSLT 3.0 中变得更聪明一些,但我更喜欢命名模板方法的清晰度。
The use of XSLT 3 and the request for a "recursive" approach while wanting to "iterate" makes me wonder whether xsl:iterate
can help: XSLT 3 的使用和在想要“迭代”时对“递归”方法的请求让我想知道
xsl:iterate
是否可以提供帮助:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xpath-default-namespace="http://www.tei-c.org/ns/1.0"
xmlns="http://www.tei-c.org/ns/1.0"
exclude-result-prefixes="#all"
version="3.0">
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="div[p and app]">
<xsl:copy>
<p>
<xsl:iterate select="app">
<xsl:param name="text" select="p"/>
<xsl:on-completion select="$text"/>
<xsl:sequence select="substring-before($text, lem),
.[contains($text, lem)]"/>
<xsl:next-iteration>
<xsl:with-param name="text" select="substring-after($text, lem)"/>
</xsl:next-iteration>
</xsl:iterate>
</p>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I don't think you need recursion, if I've understood what you're trying to do.我不认为你需要递归,如果我明白你想做什么的话。 Here's how I might attack the problem:
以下是我可能会如何解决这个问题:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:tei="http://www.tei-c.org/ns/1.0" xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs tei" version="3.0"
xpath-default-namespace="http://www.tei-c.org/ns/1.0">
<xsl:template match="p/text()">
<!-- find the apps that applies to the current text node -->
<xsl:variable name="apps" select="ancestor::div/app"/>
<!-- parse the text node into a sequence of 1-char strings
This weird trick uses string-to-codepoints() to tokenize
the string into a sequence of character codepoints, and
then uses codepoints-to-string() to turn each integer
codepoint back into a 1-char string, yielding a sequence
of characters
-->
<xsl:variable name="characters" select="
for $codepoint in
string-to-codepoints(.)
return
codepoints-to-string($codepoint)
"/>
<!-- for each character, output a matching app if
there is one, or otherwise the character itself
-->
<xsl:for-each select="$characters">
<xsl:variable name="character" select="."/>
<xsl:variable name="app" select="$apps[lem = $character]"/>
<xsl:choose>
<xsl:when test="$app">
<xsl:copy-of select="$app"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</xsl:template>
<!-- discard app elements -->
<xsl:template match="app"/>
<!-- copy everything else -->
<xsl:mode on-no-match="shallow-copy"/>
</xsl:stylesheet>
Applied to:应用于:
<div xmlns="http://www.tei-c.org/ns/1.0">
<p>SOMEWONDERFULOLDTEXT</p>
<app>
<lem>O</lem>
<rdg>Ø</rdg>
</app>
<app>
<lem>W</lem>
<rdg>V</rdg>
</app>
<app>
<lem>O</lem>
<rdg>Ö</rdg>
</app>
<app>
<lem>E</lem>
<rdg>Ë</rdg>
<rdg>ę</rdg>
</app>
</div>
Produces result:产生结果:
<div xmlns="http://www.tei-c.org/ns/1.0">
<p>S<app>
<lem>O</lem>
<rdg>Ø</rdg>
</app><app>
<lem>O</lem>
<rdg>Ö</rdg>
</app>M<app>
<lem>E</lem>
<rdg>Ë</rdg>
<rdg>ę</rdg>
</app><app>
<lem>W</lem>
<rdg>V</rdg>
</app><app>
<lem>O</lem>
<rdg>Ø</rdg>
</app><app>
<lem>O</lem>
<rdg>Ö</rdg>
</app>ND<app>
<lem>E</lem>
<rdg>Ë</rdg>
<rdg>ę</rdg>
</app>RFUL<app>
<lem>O</lem>
<rdg>Ø</rdg>
</app><app>
<lem>O</lem>
<rdg>Ö</rdg>
</app>LDT<app>
<lem>E</lem>
<rdg>Ë</rdg>
<rdg>ę</rdg>
</app>XT</p>
</div>
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