根据属性的排序顺序重新映射 Object 数组

Question

Let's see I have a data in following structure

[
    {
        "Id": "xyz7",
        "CurrentRow": 0,
        "ReportTime": "2022-07-18T09:00:00+00:00",
        "ExitTime": null,
        "DateField": "2022-07-18"
    },
    {
        "Id": "xyz8",
        "CurrentRow": 1,
        "ReportTime": "2022-07-18T08:00:00+00:00",
        "ExitTime": null,
        "DateField": "2022-07-18"
    },
    {
        "Id": "wxyz0",
        "CurrentRow": 0,
        "ReportTime": "2022-07-19T00:00:00+00:00",
        "ExitTime": null,
        "DateField": "2022-07-19"
    },
    {
        "Id": "wxyz1",
        "CurrentRow": 1,
        "ReportTime": "2022-07-19T00:00:00+00:00",
        "ExitTime": null
        "DateField": "2022-07-19"
    }
]

If I have to say sort the structure based on ReportTime of Date: 2022-07-18, that will change the CurrentRow of entries for DateField 2022-07-18 as 0 to 1 (as it will now belong to 1st Index) and for 2nd entry 1 - 0.

In addition, the CurrentRow of other entries (for other date shall also be adapted if they were same as that of day being sorted.)

In order to achieve this my implementation goes like,

I convert the structure to a two dimensional array based on CurrentRow.

Index in dimension 1, represents the CurrentRow. The element of array will be an array of specific data entry like [entry_for_date_18,entry_for_date_19] (Kind of spread sheet with date as columns and CurrentRow as rows.

And then in order to sort, I pick all the entries for a particular date, sort it, and collect it with the original CurrentRow. (Pass 1).

Then I go and update the CurrentRow of original array, using the index (pass 2).

eg pseudo code:

 for(let i=0;i<sortedDayArray.length;i++){
   findByInOriginalArray(sortedDayArray[i].CurrentRow).updateCurrentRowTo(i)
  }

Was wondering if there is a better or more efficient way to do that, using map?

Answer 1

This is how I got your question: you want to sort your array based on ReportTime , then re-arrange CurrentRow based on its position in DateField and this is the data you are expecting:

[
  {
    Id: 'xyz8',
    CurrentRow: 0,
    ReportTime: '2022-07-18T08:00:00+00:00',
    ExitTime: null,
    DateField: '2022-07-18'
  },
  {
    Id: 'xyz7',
    CurrentRow: 1,
    ReportTime: '2022-07-18T09:00:00+00:00',
    ExitTime: null,
    DateField: '2022-07-18'
  },
  {
    Id: 'wxyz0',
    CurrentRow: 0,
    ReportTime: '2022-07-19T00:00:00+00:00',
    ExitTime: null,
    DateField: '2022-07-19'
  },
  {
    Id: 'wxyz1',
    CurrentRow: 1,
    ReportTime: '2022-07-19T00:00:00+00:00',
    ExitTime: null,
    DateField: '2022-07-19'
  }
]

this is the code I came up with:

var tempRow = 0;
var tempDate = ''

YOUR_ARRAY
    .sort((a, b) => (a.ReportTime > b.ReportTime) ? 1 : ((b.ReportTime > a.ReportTime) ? -1 : 0))
    .forEach((row, i) => {
        if (row.DateField != tempDate) {
            tempDate = row.DateField
            tempRow = 0
        }
        row.CurrentRow = tempRow
        tempRow++
    })